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This approach uses the Union-Find data structure to manage connectivity between variables. The core idea is to group variables that are known to be equal using '=='. After processing all such equations, we then check the '!=' equations to ensure that connected variables (i.e., variables that are in the same component) are not incorrectly marked as not equal.
Steps:
Time Complexity: O(n * α(n)) where n is the number of equations, and α is the inverse Ackermann function.
Space Complexity: O(1) as we are using a fixed-size array of 26 characters.
1class Solution:
2 def find(self, parent, x):
3 if parent[x] != x:
4 parent[x] = self.
The Python solution employs similar methods to handle union and find operations. The character indices are calculated using ord to map variable names to indices. Therefore, we use these indices for connectivity checks and operations.
Another method is to visualize the problem as a graph and determine if the '==' relations create valid partitions without violating '!=' conditions. This is managed using a BFS approach.
Steps:
Time Complexity: O(n) where n is the number of equations as each one is processed once during graph building and inequality checks.
Space Complexity: O(1) as it uses a fixed-size 26x26 adjacency matrix.
The JavaScript solution builds an adjacency list to identify direct or indirect equality connectivity for all variables. The BFS function reviews this list to validate '!=' relations, returning false when a conflict is found. Each inequality condition is individually analyzed without revisiting cleared sections.