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This approach involves splitting the given string into words, reversing each word individually, and then joining them back together.
Time Complexity: O(n), where n is the length of the string.
Space Complexity: O(1), as only a constant amount of extra space is used.
1def reverseWords(s):
2 words = s.split()
3 return ' '.join(word[::-1] for word in words)
4
5s = "Let's take LeetCode contest"
6print(reverseWords(s))In Python, we split the string into words, reverse each word, and then join them back together with spaces.
In this C solution, a two-pointer technique is applied to reverse individual words within the string in place, using a helper function.