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To maximize the like-time coefficient, we can sort the satisfaction levels in non-descending order and calculate the possible like-time coefficients by considering prefixes from the end of the sorted array. This allows us to selectively choose higher satisfaction dishes to maximize the total like-time coefficient.
Time Complexity: O(n log n) due to sorting.
Space Complexity: O(1) for using a constant amount of extra space.
1#include <iostream>
2#include <vector>
3#include <algorithm>
4
5int maxSatisfaction(std::vector<int>& satisfaction) {
6    std::sort(satisfaction.begin(), satisfaction.end(), std::greater<int>());
7    int total = 0, sum = 0;
8    for (int s : satisfaction) {
9        sum += s;
10        if (sum > 0) {
11            total += sum;
12        } else {
13            break;
14        }
15    }
16    return total;
17}
18
19int main() {
20    std::vector<int> satisfaction = {-1, -8, 0, 5, -9};
21    std::cout << maxSatisfaction(satisfaction);
22    return 0;
23}This C++ solution similarly sorts the satisfaction levels in decreasing order. It then iteratively accumulates the like-time coefficient, stopping when the running sum becomes non-positive.
An alternative approach involves using dynamic programming to maximize the like-time coefficient. We maintain a DP table where `dp[i]` represents the maximum like-time coefficient attainable using the first `i` dishes. This approach computes overlap coefficients dynamically using state transitions calculated for each dish considered.
Time Complexity: O(n^2)
Space Complexity: O(n)
1
class Program {
    static int MaxSatisfaction(int[] satisfaction) {
        Array.Sort(satisfaction);
        int n = satisfaction.Length;
        int[] dp = new int[n + 1];
        for (int i = n - 1; i >= 0; i--) {
            for (int t = 0; t <= i; t++) {
                dp[t] = Math.Max(dp[t], dp[t + 1] + satisfaction[i] * (t + 1));
            }
        }
        return dp[0];
    }
    static void Main() {
        int[] satisfaction = {4, 3, 2};
        Console.WriteLine(MaxSatisfaction(satisfaction));
    }
}The C# program adopts dynamic programming to make state transitions represent time indices for prepared dishes, updating choices dynamically to achieve the maximum like-time coefficient.