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This approach involves successively dividing the number n by 4 to check if it results in 1. If n is a power of four, repeatedly dividing it by 4 should eventually reduce it to 1 with no remainder.
Time Complexity: O(log4 n) due to repeated division.
Space Complexity: O(1) because no additional space is used.
1
bool isPowerOfFour(int n) {
if (n <= 0) return false;
while (n % 4 == 0) {
n /= 4;
}
return n == 1;
}Similar to the C version, this C++ function checks divisibility by 4 and continuously divides by 4 until n reaches 1, confirming it's a power of four.
This approach harnesses logarithms to determine if a number is a power of four. For a number n to be a power of four, the logarithm base 4 of n should be an integer. Utilizing the change of base formula, this can be checked without directly using base 4 logarithm functions.
Time Complexity: O(1) as logarithmic operations are constant time.
Space Complexity: O(1).
1using System;
2
3public class Solution {
4 public bool IsPowerOfFour(int n) {
5 if (n <= 0) return false;
6 double log_val = Math.Log10(n) / Math.Log10(4);
7 return Math.Floor(log_val) == log_val;
8 }
9}This C# code checks if n is a power of four using logarithms, ensuring the computed value is a whole number.