Sponsored
Sponsored
In this approach, we solve the problem by checking all possible combinations or configurations naively. Although not efficient for large inputs, this approach is often straightforward and can provide insights into the problem structure.
Time Complexity: O(n).
Space Complexity: O(1), as no extra space is used other than loop variables.
1#include <stdio.h>
2
3void solve(int n) {
4 // A simple C program illustrating brute force
5 for(int i = 0; i < n; i++) {
6 printf("%d ", i);
7 }
8 printf("\n");
9}
10
11int main() {
12 solve(10);
13 return 0;
14}This C solution iterates over all numbers from 0 to n-1, printing each number. It's a simple example of a brute force approach.
This approach utilizes dynamic programming to optimize the solution by storing interim results and eliminating redundant calculations seen in a brute force approach. This method can significantly improve efficiency when dealing with complex recursive problems.
Time Complexity: O(n).
Space Complexity: O(n) due to the storage array.
1using System;
class Solution {
static int[] dp = new int[1000];
static int Solve(int n) {
if (n <= 1) return n;
if (dp[n] != -1) return dp[n];
return dp[n] = Solve(n-1) + Solve(n-2);
}
static void Main() {
Array.Fill(dp, -1);
Console.WriteLine(Solve(10));
}
}In C#, dynamic programming is used for calculating Fibonacci numbers, with an array for memoization to optimize computation.