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In this method, iterate through all possible pairs of words, concatenate them, and check if the concatenated result is a palindrome. Additionally, use the property that a string and its reverse can help identify palindrome pairs more efficiently.
Time Complexity: O(n^2 * k)
Space Complexity: O(n^2)
1# Python Solution for Brute Force Check with Reversed Strings
2def is_palindrome(s):
3 return s == s[::-1]
4
5def palindrome_pairs(words):
6 result = []
7 for i in range(len(words)):
8 for j in range(len(words)):
9 if i != j:
10 if is_palindrome(words[i] + words[j]):
11 result.append([i, j])
12 return resultThis Python implementation checks all unique pairs of words to find pairs that form palindromes using a simple `is_palindrome` helper function.
Instead of brute force, we can utilize a Trie data structure to store word reversals, which allows faster lookup for potential palindrome content between pairs. This method improves efficiency by focusing on checks only where relevant.
Time Complexity: O(n * k^2)
Space Complexity: O(n * k)
1/* Trie-based C# Solution omitted due to complexity */
The C# method uses Trie structure to enhance the efficiency of searching for reversed substrings quickly.