Sponsored
Sponsored
In this method, iterate through all possible pairs of words, concatenate them, and check if the concatenated result is a palindrome. Additionally, use the property that a string and its reverse can help identify palindrome pairs more efficiently.
Time Complexity: O(n^2 * k)
Space Complexity: O(n^2)
1/* JavaScript Solution for Brute Force Check with Reversed Strings */
2function isPalindrome(s) {
3 return s === s.split('').reverse().join('');
4}
5
6function palindromePairs(words) {
7 const result = [];
8 for (let i = 0; i < words.length; i++) {
9 for (let j = 0; j < words.length; j++) {
10 if (i !== j && isPalindrome(words[i] + words[j])) {
11 result.push([i, j]);
12 }
13 }
14 }
15 return result;
16}The JavaScript approach operates similarly to other languages using a nested loop to generate pairs and checks for palindromes using a simple function `isPalindrome`.
Instead of brute force, we can utilize a Trie data structure to store word reversals, which allows faster lookup for potential palindrome content between pairs. This method improves efficiency by focusing on checks only where relevant.
Time Complexity: O(n * k^2)
Space Complexity: O(n * k)
1/* Trie-based Java Solution omitted due to complexity */This version constructs a Trie for word reversals and performs quick lookup checks against word segments.