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This approach uses the SQL query constructs to fetch the nth highest salary directly from the database. We will utilize ORDER BY, DISTINCT, LIMIT, and OFFSET to achieve this.
Steps:
SELECT DISTINCT
.ORDER BY salary DESC
.LIMIT
and OFFSET
to skip the first n-1 results and take the nth result if it exists.1# Placeholder function for SQL query in Python
2def get_nth_highest_salary_sql(n):
3 return f"SELECT DISTINCT salary FROM Employee ORDER BY salary DESC LIMIT 1 OFFSET {n-1}"
4
5# Execute this query using a Python SQL library like sqlite3 or SQLAlchemy.
This Python function generates a SQL query string. Execute this query using libraries like sqlite3 or SQLAlchemy in a database context.
In this approach, we will use the DENSE_RANK()
window function available in SQL to assign ranks to salaries based on their value.
Steps:
DENSE_RANK
by partitioning properly.n
.
This Python function returns a SQL query string using DENSE_RANK
to rank salaries. Execute it in a database environment for results.