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This approach revolves around using a stack to efficiently identify and remove the substrings "AB" and "CD" from the given string. By traversing each character of the string:
The characters that remain on the stack are the ones that could not form any removable patterns, thus forming the result string.
Time Complexity: O(n), where n is the length of the string.
Space Complexity: O(n), to store the stack elements, based on the worst case where no pairs are removed.
1import java.util.Stack;
2
3public class MinLength {
4 public static int minLengthAfterRemovals(String s) {
5
The Java solution uses Java's Stack
class to perform the necessary stack operations and process each character in the string to achieve the reduced string.
This technique uses a two-pointer approach to reduce the string by altering it in place. The core idea is to selectively overwrite positions in the string:
After reaching the end of the string, the length of the string from the start to the write pointer represents the reduced string length.
Time Complexity: O(n), dependent on examining each character once.
Space Complexity: O(1), as no additional data structures are used.
This Java solution translates the two-pointer logic into Java by deconstructing the input to a character array. This allows direct manipulation similar to C-style string approaches, achieving an in-place modification.