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In this approach, we prioritize removing the substring with a higher score first. We utilize a stack to efficiently traverse and remove substrings from the string. Given two substrings 'ab' and 'ba', and their scores x and y, we decide which to remove first based on the higher score. The stack helps in processing the string in a single pass, adding character by character and checking for the target substring ending each time.
Time Complexity: O(n), where n is the length of the string.
Space Complexity: O(n), for the stack used in substring removal.
1function maxScore(s, x, y) {
2 let score = 0;
3 let stack = [];
4 let first = x > y ? 'a' : 'b';
5 let second = x > y ? 'b' : 'a';
6 let firstPoints = x > y ? x : y;
7 let secondPoints = x > y ? y : x;
8
9 // Remove higher score patterns first
10 for (let char of s) {
11 if (stack.length > 0 && stack[stack.length - 1] === first && char === second) {
12 stack.pop();
13 score += firstPoints;
14 } else {
15 stack.push(char);
16 }
17 }
18
19 // Second pass to remove remaining patterns
20 let secondPass = [];
21 while (stack.length > 0) {
22 let char = stack.pop();
23 if (secondPass.length > 0 && secondPass[secondPass.length - 1] === second && char === first) {
24 secondPass.pop();
25 score += secondPoints;
26 } else {
27 secondPass.push(char);
28 }
29 }
30
31 return score;
32}
33
34let s = "cdbcbbaaabab";
35let x = 4;
36let y = 5;
37console.log(maxScore(s, x, y));This JavaScript solution handles string parsing using arrays to perform stack-like operations. The main pass removes the higher score pattern, followed by a secondary pass to clear remaining lower score patterns.
The Two-Pointer approach leverages two pointers to parse through the string and eliminate substrings optimally. By managing two scanning points, determining which pattern to remove can be executed with minimal operations, optimizing score calculation effectively.
Time Complexity: O(n), where n is the length of the string.
Space Complexity: O(n), due to stack arrays used to manage character tracking.
1using System.Text;
using System.Collections.Generic;
public class MaxScore {
public static int MaxScoreFunc(string s, int x, int y) {
int score = 0;
StringBuilder stack = new StringBuilder();
char first = x > y ? 'a' : 'b';
char second = x > y ? 'b' : 'a';
int firstPoints = x > y ? x : y;
int secondPoints = x > y ? y : x;
foreach (char c in s) {
if (stack.Length > 0 && stack[stack.Length - 1] == first && c == second) {
stack.Length--;
score += firstPoints;
} else {
stack.Append(c);
}
}
s = stack.ToString();
stack = new StringBuilder();
foreach (char c in s) {
if (stack.Length > 0 && stack[stack.Length - 1] == second && c == first) {
stack.Length--;
score += secondPoints;
} else {
stack.Append(c);
}
}
return score;
}
public static void Main(string[] args) {
string s = "cdbcbbaaabab";
int x = 4;
int y = 5;
Console.WriteLine(MaxScoreFunc(s, x, y));
}
}Within this C# implementation, we apply a StringBuilder to efficiently manage mutable strings as pointers traverse through data. This achieves a balance between concise sunflower manipulations whilst calculating maximum scores through iterated logic.