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One simple yet effective way to tackle this problem is to track the minimum and maximum values as we iterate over the arrays, since each array is sorted in ascending order. We initialize the maximum distance as zero. For each array except the first one, calculate the possible distance using the current array's first element with the global maximum, and the current array's last element with the global minimum. Update the global minimum and maximum as you traverse each array. This approach ensures all distance calculations only consider meaningful pairs from different arrays and efficiently computes the result in a single pass.
Time Complexity: O(m) where m is the number of arrays. Space Complexity: O(1) as we are only using constant extra space.
1var maxDistance = function(arrays) {
2 let maxDist = 0;
3 let minVal = arrays[0][0];
4
JavaScript solution incorporates dynamic variable declaration and modern ES6 syntax to encapsulate logical operations while ensuring minimal computational steps to derive the solution.
A naive brute force approach would involve iterating over each pair of arrays and comparing all possible combinations of elements from both arrays. While this method ensures completeness of coverage for all potential maximum distance computations, it results in a less efficient O(m2 * n) complexity where n is the average number of elements in one array. It serves as a solid baseline comparison for the more efficient approach.
Time Complexity: O(m2 * n) where m is the number of arrays and n is the average number of elements in each array. Space Complexity: O(1), constant space aside from an output variable.
This straightforward Python solution offers visibility into all examined array components necessary for distance computation, albeit with slower performance due to increased O(m2) general operation cycles inherent to brute force checking.