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This approach involves using a two-pointer technique to check if a string from the dictionary is a subsequence of the given string s. We iterate through each word in the dictionary and for each word, use two pointers to traverse through the word and s. If all characters of the word are found in the same order in s, then it's a valid word. We maintain a result variable to track the longest valid word found so far, and if multiple are of the same length, we track the smallest lexicographical order.
s. This is because we potentially traverse the entire string for each dictionary word.1function isSubsequence(s, word) {
2 let i = 0, j = 0;
3 while (i < s.length && j < word.
This JavaScript implementation leverages a two-pointer strategy similar to other language implementations to check if each word in the dictionary can be formed by deleting characters in s. The script iterates through the dictionary to track the longest valid result.
This approach involves sorting the dictionary by length (descending) and lexicographical order (ascending). By sorting first, you can ensure that you are checking the longest available words first while resolving ties based on the smallest alphabetical order. We then iterate through this sorted list and use a function to check if a word is a valid subsequence of s.
1def is_subsequence(s, word):
This Python implementation uses sorting to align words by the desirable evaluation order: first longest, then smallest lexicographically. The `is_subsequence` function checks if a word is a subsequence of `s`, as before accomplished using iterators for efficiency.