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The idea is to determine which city does not have any outgoing paths. This can be done by keeping track of all cities that appear as the starting city of a path. The destination city is the one that is not in this set but appears as an ending city in the path list.
Time Complexity: O(n^2) due to linear checks within loops.
Space Complexity: O(n), where n is the number of cities.
1#include <stdio.h>
2#include <string.h>
3#include <stdbool.h>
4
5char* destCity(char*** paths, int pathsSize, int* pathsColSize) {
6 bool outgoing[100] = {false};
7 char* cities[200];
8 int cityCount = 0;
9
10 for (int i = 0; i < pathsSize; i++) {
11 int startIndex = -1, endIndex = -1;
12 for (int j = 0; j < cityCount; j++) {
13 if (strcmp(cities[j], paths[i][0]) == 0) startIndex = j;
14 if (strcmp(cities[j], paths[i][1]) == 0) endIndex = j;
15 }
16 if (startIndex == -1) cities[cityCount++] = paths[i][0];
17 if (endIndex == -1) cities[cityCount++] = paths[i][1];
18
19 outgoing[startIndex] = true;
20 }
21
22 for(int i = 0; i < pathsSize; i++) {
23 char* destination = paths[i][1];
24 int j;
25 for (j = 0; j < cityCount; j++) {
26 if (strcmp(cities[j], destination) == 0 && !outgoing[j]) {
27 return destination;
28 }
29 }
30 }
31 return "";
32}
33This C solution uses an array to simulate a set to track which cities have outgoing paths. We iterate over the paths, storing cities in an array and marking those that appear as starting cities. Finally, we check which city does not appear as a starting city and return it as the destination.
This approach involves counting occurrences of each city as an endpoint. The destination city will be the one whose occurrence as a destination is not matched by an occurrence as a start.
Time Complexity: O(n^2), since it includes iterating through paths multiple times.
Space Complexity: O(n) for storing city names.
1#include
This C solution involves copying the destination cities into an array and checking each destination city against the start cities. The city not found among the start cities is returned as the destination city.