1import java.util.ArrayList;
2import java.util.List;
3
4public class Main {
5    public static List<Integer> findConsecutiveNumbers(int[] nums) {
6        List<Integer> result = new ArrayList<>();
7        int count = 1;
8        for (int i = 1; i < nums.length; i++) {
9            if (nums[i] == nums[i - 1]) {
10                count++;
11                if (count == 3 && !result.contains(nums[i])) {
12                    result.add(nums[i]);
13                }
14            } else {
15                count = 1;
16            }
17        }
18        return result;
19    }
20
21    public static void main(String[] args) {
22        int[] nums = {1, 1, 1, 2, 1, 2, 2};
23        System.out.println(findConsecutiveNumbers(nums));
24    }
25}
26

1#include <iostream>
#include <unordered_map>
#include <vector>
using namespace std;

vector<int> findConsecutiveNumbers(vector<int>& nums) {
    unordered_map<int, int> count;
    vector<int> result;
    int consecutive = 1;
    for (size_t i = 1; i < nums.size(); ++i) {
        if (nums[i] == nums[i - 1]) {
            consecutive++;
            if (consecutive == 3 && count[nums[i - 1]] != 1) {
                result.push_back(nums[i]);
                count[nums[i]] = 1;
            }
        } else {
            consecutive = 1;
        }
    }

    return result;
}

int main() {
    vector<int> nums = {1, 1, 1, 2, 1, 2, 2};
    vector<int> result = findConsecutiveNumbers(nums);
    for (int num : result) cout << num << endl;
    return 0;
}