1import java.util.ArrayList;
2import java.util.List;
3
4public class Main {
5    public static List<Integer> findConsecutiveNumbers(int[] nums) {
6        List<Integer> result = new ArrayList<>();
7        int count = 1;
8        for (int i = 1; i < nums.length; i++) {
9            if (nums[i] == nums[i - 1]) {
10                count++;
11                if (count == 3 && !result.contains(nums[i])) {
12                    result.add(nums[i]);
13                }
14            } else {
15                count = 1;
16            }
17        }
18        return result;
19    }
20
21    public static void main(String[] args) {
22        int[] nums = {1, 1, 1, 2, 1, 2, 2};
23        System.out.println(findConsecutiveNumbers(nums));
24    }
25}
26

1using System;
using System.Collections.Generic;

class Program {
    static List<int> FindConsecutiveNumbers(int[] nums) {
        var count = new Dictionary<int, bool>();
        var result = new List<int>();
        int consecutive = 1;
        for (int i = 1; i < nums.Length; i++) {
            if (nums[i] == nums[i - 1]) {
                consecutive++;
                if (consecutive == 3 && !count.ContainsKey(nums[i])) {
                    result.Add(nums[i]);
                    count[nums[i]] = true;
                }
            } else {
                consecutive = 1;
            }
        }
        return result;
    }

    static void Main() {
        int[] nums = {1, 1, 1, 2, 1, 2, 2};
        var result = FindConsecutiveNumbers(nums);
        foreach (var num in result) {
            Console.WriteLine(num);
        }
    }
}