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This method involves splitting the sentence into words and verifying the circular property by manually comparing the last character of one word with the first character of the next word, including checking the condition from the last word to the first word.
Time complexity: O(n), where n is the length of the sentence.
Space complexity: O(1), as no additional data structures are used.
1
The Python solution splits the sentence into a list of words and checks the last character of each word against the first character of the next word. It further checks the consistency between the first and last word.
This approach uses two pointers to traverse through the sentence. One pointer identifies word endings, the other starts at the first character of new words. This methodology avoids splitting the sentence into words explicitly.
Time complexity: O(n), due to the traversal of the sentence.
Space complexity: O(1), as it involves no auxiliary storage.
1function isCircularSentence(sentence) {
2 let n = sentence.length;
3 if (sentence[0] !== sentence[n - 1]) return false;
4
5 for (let i = 1; i < n - 1; i++) {
6 if (sentence[i] === ' ' && sentence[i - 1] !== sentence[i + 1]) {
7 return false;
8 }
9 }
10
11 return true;
12}
13
14let sentence = "leetcode exercises sound delightful";
15console.log(isCircularSentence(sentence));The JavaScript logic here efficiently processes each character onwards, particularly leveraging word separation points (' ') to affirm the circular structure.