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This method involves splitting the sentence into words and verifying the circular property by manually comparing the last character of one word with the first character of the next word, including checking the condition from the last word to the first word.
Time complexity: O(n), where n is the length of the sentence.
Space complexity: O(1), as no additional data structures are used.
1
This solution breaks the sentence into words, then checks each adjacent pair for circular continuity. The check is repeated from the last word back to the first, ensuring a complete loop.
This approach uses two pointers to traverse through the sentence. One pointer identifies word endings, the other starts at the first character of new words. This methodology avoids splitting the sentence into words explicitly.
Time complexity: O(n), due to the traversal of the sentence.
Space complexity: O(1), as it involves no auxiliary storage.
1def is_circular_sentence(sentence):
2 n = len(sentence)
3 if sentence[0] != sentence[-1]:
4 return False
5
6 for i in range(1, n - 1):
7 if sentence[i] == ' ' and sentence[i - 1] != sentence[i + 1]:
8 return False
9
10 return True
11
12sentence = "leetcode exercises sound delightful"
13print(is_circular_sentence(sentence))This Python code traverses the sentence with a straightforward loop to monitor space-separated boundaries and verify character connectivity in a circular fashion.