We can simulate the number of passengers in the car at each kilometer using a difference array. For each trip, increase the passenger count at fromi
and decrease it at toi
. Then, iterate through this array to calculate the actual number of passengers at each point, checking if it ever exceeds the capacity.
Time Complexity: O(n + m) where n is the number of trips and m is the max distance (1000).
Space Complexity: O(m) for the difference array.
1var carPooling = function(trips, capacity) {
2 let passengerChanges = new Array(1001).fill(0);
3
4 for (let [numPassengers, from, to] of trips) {
5 passengerChanges[from] += numPassengers;
6 passengerChanges[to] -= numPassengers;
7 }
8
9 let currentPassengers = 0;
10 for (let change of passengerChanges) {
11 currentPassengers += change;
12 if (currentPassengers > capacity) return false;
13 }
14
15 return true;
16};
A difference array allows for tracking passenger metrics at each potential stop point, with each trip contributing positively and negatively to running totals. We validate this against capacity constraints continuously.
In this approach, we treat each pick-up and drop-off as events. We collect all events, sort them based on location, and then simulate the process of picking up and dropping off passengers by iterating through events in order, checking if it ever exceeds the car's capacity.
Time Complexity: O(n log n), driven by sorting events.
Space Complexity: O(n).
1import java.util.*;
2
3public class Solution {
4 public boolean carPooling(int[][] trips, int capacity) {
5 List<int[]> events = new ArrayList<>();
6
7 for (int[] trip : trips) {
8 events.add(new int[]{trip[1], trip[0]}); // pickup
9 events.add(new int[]{trip[2], -trip[0]}); // drop-off
10 }
11
12 events.sort((a, b) -> a[0] - b[0]);
13
14 int currentPassengers = 0;
15 for (int[] event : events) {
16 currentPassengers += event[1];
17 if (currentPassengers > capacity) return false;
18 }
19
20 return true;
21 }
22}
Represented as pick-up and drop-off events, we sort and sequentially evaluate each event in terms of its change to car burdens, returning a boolean determination.