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The iterative approach involves simulating each day in a loop, tracking both the weeks and individual days. We'll add the appropriate amount of money for each day based on the rules provided. This approach leverages basic looping constructs and conditionally increments the sums based on the day of the week.
Time Complexity: O(n), where n is the number of days. Each day is processed once.
Space Complexity: O(1), only a constant amount of space is used.
1class Solution {
2 public int totalMoney(int n) {
3 int total = 0;
4 int week = 0;
5 for (int i = 0; i < n; i++) {
6 if (i % 7 == 0) {
7 week++;
8 }
9 total += week + (i % 7);
10 }
11 return total;
12 }
13 public static void main(String[] args) {
14 Solution sol = new Solution();
15 System.out.println(sol.totalMoney(10));
16 }
17}
18The Java solution employs a recursive loop to handle increment calculations similarly to the C and C++ solutions. The modular operation helps determine when new weeks start, while daily additions align with problem constraints.
The mathematical approach seeks to minimize iterations by using formulae to directly compute sums based on weeks, leveraging arithmetic series properties. This method is typically more efficient and concise.
Time Complexity: O(1).
Space Complexity: O(1).
1def
This Python code leverages integer division and sum formulas to provide optimal results without loops, maximizing efficiency.