Sponsored
Sponsored
This approach involves using a hash map or dictionary to count the number of occurrences of each integer in the array. After counting, we identify numbers that appeared only once and find the maximum among them. This way, we can efficiently determine the largest single number.
Time Complexity: O(n^2) in worst case for counting and sorting (since sorting involves iterating the elements list).
Space Complexity: O(n) for storing numbers and their counts.
1#include <stdio.h>
2#include <stdlib.h>
3
4struct element {
5 int num;
6 int count;
7};
8
9int compare(const void *a, const void *b) {
10 return ((struct element *)b)->num - ((struct element *)a)->num;
11}
12
13int biggestSingleNumber(int* nums, int numsSize) {
14 if (numsSize == 0) return -1;
15
16 struct element elements[numsSize];
17 int elementsSize = 0;
18 int found;
19
20 for (int i = 0; i < numsSize; i++) {
21 found = 0;
22 for (int j = 0; j < elementsSize; j++) {
23 if (elements[j].num == nums[i]) {
24 elements[j].count++;
25 found = 1;
26 break;
27 }
28 }
29 if (!found) {
30 elements[elementsSize].num = nums[i];
31 elements[elementsSize].count = 1;
32 elementsSize++;
33 }
34 }
35
36 qsort(elements, elementsSize, sizeof(struct element), compare);
37
38 for (int i = 0; i < elementsSize; i++) {
39 if (elements[i].count == 1) {
40 return elements[i].num;
41 }
42 }
43 return -1;
44}
45
46int main() {
47 int nums[] = {8, 8, 3, 3, 1, 4, 5, 6};
48 int result = biggestSingleNumber(nums, sizeof(nums)/sizeof(nums[0]));
49 if (result == -1) {
50 printf("null\n");
51 } else {
52 printf("%d\n", result);
53 }
54 return 0;
55}In this C code, we define a structure to store the integers and their counts. We iterate through the array, counting occurrences. After populating the list, we sort it and look for the largest number with a count of 1.
This approach involves sorting the numbers first. After sorting, we can iterate through the list to count numbers that appear consecutively more than once and skip them. The largest number with only one occurrence is then the answer.
Time Complexity: O(n log n) due to sorting.
Space Complexity: O(1) as we sort in place.
1def
This Python script first sorts the list in descending order. It then iterates through the sorted list, identifying the largest single number using simple comparisons.